Finite Math Examples

$\frac{9 x}{(x + 1) {(x + 4)}^{2}} = \frac{a}{1} + \frac{b}{x + 4} + \frac{c}{{(x + 4)}^{2}}$

Step 1

Move all the expressions to the left side of the equation.

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Step 1.1

Subtract $\frac{a}{1}$ from both sides of the equation.

$\frac{9 x}{(x + 1) {(x + 4)}^{2}} - \frac{a}{1} = \frac{b}{x + 4} + \frac{c}{{(x + 4)}^{2}}$

Step 1.2

Subtract $\frac{b}{x + 4}$ from both sides of the equation.

$\frac{9 x}{(x + 1) {(x + 4)}^{2}} - \frac{a}{1} - \frac{b}{x + 4} = \frac{c}{{(x + 4)}^{2}}$

Step 1.3

Subtract $\frac{c}{{(x + 4)}^{2}}$ from both sides of the equation.

$\frac{9 x}{(x + 1) {(x + 4)}^{2}} - \frac{a}{1} - \frac{b}{x + 4} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2

Simplify $\frac{9 x}{(x + 1) {(x + 4)}^{2}} - \frac{a}{1} - \frac{b}{x + 4} - \frac{c}{{(x + 4)}^{2}}$ .

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Step 2.1

Divide $a$ by $1$ .

$\frac{9 x}{(x + 1) {(x + 4)}^{2}} - a - \frac{b}{x + 4} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.2

To write $- \frac{b}{x + 4}$ as a fraction with a common denominator, multiply by $\frac{(x + 1) (x + 4)}{(x + 1) (x + 4)}$ .

$- a + \frac{9 x}{(x + 1) {(x + 4)}^{2}} - \frac{b}{x + 4} \cdot \frac{(x + 1) (x + 4)}{(x + 1) (x + 4)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.3

Write each expression with a common denominator of $(x + 1) {(x + 4)}^{2}$ , by multiplying each by an appropriate factor of $1$ .

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Step 2.3.1

Multiply $\frac{b}{x + 4}$ by $\frac{(x + 1) (x + 4)}{(x + 1) (x + 4)}$ .

$- a + \frac{9 x}{(x + 1) {(x + 4)}^{2}} - \frac{b ((x + 1) (x + 4))}{(x + 4) ((x + 1) (x + 4))} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.3.2

Raise $x + 4$ to the power of $1$ .

$- a + \frac{9 x}{(x + 1) {(x + 4)}^{2}} - \frac{b ((x + 1) (x + 4))}{{(x + 4)}^{1} (x + 4) (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.3.3

Raise $x + 4$ to the power of $1$ .

$- a + \frac{9 x}{(x + 1) {(x + 4)}^{2}} - \frac{b ((x + 1) (x + 4))}{{(x + 4)}^{1} {(x + 4)}^{1} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.3.4

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$- a + \frac{9 x}{(x + 1) {(x + 4)}^{2}} - \frac{b ((x + 1) (x + 4))}{{(x + 4)}^{1 + 1} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.3.5

Add $1$ and $1$ .

$- a + \frac{9 x}{(x + 1) {(x + 4)}^{2}} - \frac{b ((x + 1) (x + 4))}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.3.6

Reorder the factors of $(x + 1) {(x + 4)}^{2}$ .

$- a + \frac{9 x}{{(x + 4)}^{2} (x + 1)} - \frac{b ((x + 1) (x + 4))}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.4

Combine the numerators over the common denominator.

$- a + \frac{9 x - b ((x + 1) (x + 4))}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.5

Simplify the numerator.

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Step 2.5.1

Apply the distributive property.

$- a + \frac{9 x + (- b x - b \cdot 1) (x + 4)}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.5.2

Multiply $- 1$ by $1$ .

$- a + \frac{9 x + (- b x - b) (x + 4)}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.5.3

Expand $(- b x - b) (x + 4)$ using the FOIL Method.

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Step 2.5.3.1

Apply the distributive property.

$- a + \frac{9 x - b x (x + 4) - b (x + 4)}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.5.3.2

Apply the distributive property.

$- a + \frac{9 x - b x \cdot x - b x \cdot 4 - b (x + 4)}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.5.3.3

Apply the distributive property.

$- a + \frac{9 x - b x \cdot x - b x \cdot 4 - b x - b \cdot 4}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.5.4

Simplify and combine like terms.

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Step 2.5.4.1

Simplify each term.

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Step 2.5.4.1.1

Multiply $x$ by $x$ by adding the exponents.

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Step 2.5.4.1.1.1

Move $x$ .

$- a + \frac{9 x - b (x \cdot x) - b x \cdot 4 - b x - b \cdot 4}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.5.4.1.1.2

Multiply $x$ by $x$ .

$- a + \frac{9 x - b x^{2} - b x \cdot 4 - b x - b \cdot 4}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.5.4.1.2

Multiply $4$ by $- 1$ .

$- a + \frac{9 x - b x^{2} - 4 b x - b x - b \cdot 4}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.5.4.1.3

Multiply $4$ by $- 1$ .

$- a + \frac{9 x - b x^{2} - 4 b x - b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.5.4.2

Subtract $b x$ from $- 4 b x$ .

$- a + \frac{9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.6

To write $- a$ as a fraction with a common denominator, multiply by $\frac{(x + 1) {(x + 4)}^{2}}{(x + 1) {(x + 4)}^{2}}$ .

$- a \cdot \frac{(x + 1) {(x + 4)}^{2}}{(x + 1) {(x + 4)}^{2}} + \frac{9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.7

Write each expression with a common denominator of $(x + 1) {(x + 4)}^{2}$ , by multiplying each by an appropriate factor of $1$ .

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Step 2.7.1

Combine $- a$ and $\frac{(x + 1) {(x + 4)}^{2}}{(x + 1) {(x + 4)}^{2}}$ .

$\frac{- a ((x + 1) {(x + 4)}^{2})}{(x + 1) {(x + 4)}^{2}} + \frac{9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.7.2

Reorder the factors of $(x + 1) {(x + 4)}^{2}$ .

$\frac{- a ((x + 1) {(x + 4)}^{2})}{{(x + 4)}^{2} (x + 1)} + \frac{9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.8

Combine the numerators over the common denominator.

$\frac{- a ((x + 1) {(x + 4)}^{2}) + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9

Simplify the numerator.

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Step 2.9.1

Apply the distributive property.

$\frac{(- a x - a \cdot 1) {(x + 4)}^{2} + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.2

Multiply $- 1$ by $1$ .

$\frac{(- a x - a) {(x + 4)}^{2} + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.3

Rewrite ${(x + 4)}^{2}$ as $(x + 4) (x + 4)$ .

$\frac{(- a x - a) ((x + 4) (x + 4)) + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.4

Expand $(x + 4) (x + 4)$ using the FOIL Method.

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Step 2.9.4.1

Apply the distributive property.

$\frac{(- a x - a) (x (x + 4) + 4 (x + 4)) + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.4.2

Apply the distributive property.

$\frac{(- a x - a) (x \cdot x + x \cdot 4 + 4 (x + 4)) + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.4.3

Apply the distributive property.

$\frac{(- a x - a) (x \cdot x + x \cdot 4 + 4 x + 4 \cdot 4) + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.5

Simplify and combine like terms.

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Step 2.9.5.1

Simplify each term.

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Step 2.9.5.1.1

Multiply $x$ by $x$ .

$\frac{(- a x - a) (x^{2} + x \cdot 4 + 4 x + 4 \cdot 4) + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.5.1.2

Move $4$ to the left of $x$ .

$\frac{(- a x - a) (x^{2} + 4 \cdot x + 4 x + 4 \cdot 4) + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.5.1.3

Multiply $4$ by $4$ .

$\frac{(- a x - a) (x^{2} + 4 x + 4 x + 16) + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.5.2

Add $4 x$ and $4 x$ .

$\frac{(- a x - a) (x^{2} + 8 x + 16) + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.6

Expand $(- a x - a) (x^{2} + 8 x + 16)$ by multiplying each term in the first expression by each term in the second expression.

$\frac{- a x \cdot x^{2} - a x (8 x) - a x \cdot 16 - a x^{2} - a (8 x) - a \cdot 16 + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.7

Simplify each term.

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Step 2.9.7.1

Multiply $x$ by $x^{2}$ by adding the exponents.

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Step 2.9.7.1.1

Move $x^{2}$ .

$\frac{- a (x^{2} x) - a x (8 x) - a x \cdot 16 - a x^{2} - a (8 x) - a \cdot 16 + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.7.1.2

Multiply $x^{2}$ by $x$ .

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Step 2.9.7.1.2.1

Raise $x$ to the power of $1$ .

$\frac{- a (x^{2} x^{1}) - a x (8 x) - a x \cdot 16 - a x^{2} - a (8 x) - a \cdot 16 + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.7.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{- a x^{2 + 1} - a x (8 x) - a x \cdot 16 - a x^{2} - a (8 x) - a \cdot 16 + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.7.1.3

Add $2$ and $1$ .

$\frac{- a x^{3} - a x (8 x) - a x \cdot 16 - a x^{2} - a (8 x) - a \cdot 16 + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.7.2

Multiply $x$ by $x$ by adding the exponents.

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Step 2.9.7.2.1

Move $x$ .

$\frac{- a x^{3} - a (x \cdot x) \cdot 8 - a x \cdot 16 - a x^{2} - a (8 x) - a \cdot 16 + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.7.2.2

Multiply $x$ by $x$ .

$\frac{- a x^{3} - a x^{2} \cdot 8 - a x \cdot 16 - a x^{2} - a (8 x) - a \cdot 16 + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.7.3

Multiply $8$ by $- 1$ .

$\frac{- a x^{3} - 8 a x^{2} - a x \cdot 16 - a x^{2} - a (8 x) - a \cdot 16 + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.7.4

Multiply $16$ by $- 1$ .

$\frac{- a x^{3} - 8 a x^{2} - 16 a x - a x^{2} - a (8 x) - a \cdot 16 + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.7.5

Rewrite using the commutative property of multiplication.

$\frac{- a x^{3} - 8 a x^{2} - 16 a x - a x^{2} - 1 \cdot 8 a x - a \cdot 16 + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.7.6

Multiply $- 1$ by $8$ .

$\frac{- a x^{3} - 8 a x^{2} - 16 a x - a x^{2} - 8 a x - a \cdot 16 + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.7.7

Multiply $16$ by $- 1$ .

$\frac{- a x^{3} - 8 a x^{2} - 16 a x - a x^{2} - 8 a x - 16 a + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.8

Subtract $a x^{2}$ from $- 8 a x^{2}$ .

$\frac{- a x^{3} - 9 a x^{2} - 16 a x - 8 a x - 16 a + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.9.9

Subtract $8 a x$ from $- 16 a x$ .

$\frac{- a x^{3} - 9 a x^{2} - 24 a x - 16 a + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} = 0$

Step 2.10

To write $- \frac{c}{{(x + 4)}^{2}}$ as a fraction with a common denominator, multiply by $\frac{x + 1}{x + 1}$ .

$\frac{- a x^{3} - 9 a x^{2} - 24 a x - 16 a + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c}{{(x + 4)}^{2}} \cdot \frac{x + 1}{x + 1} = 0$

Step 2.11

Multiply $\frac{c}{{(x + 4)}^{2}}$ by $\frac{x + 1}{x + 1}$ .

$\frac{- a x^{3} - 9 a x^{2} - 24 a x - 16 a + 9 x - b x^{2} - 5 b x - 4 b}{{(x + 4)}^{2} (x + 1)} - \frac{c (x + 1)}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.12

Combine the numerators over the common denominator.

$\frac{- a x^{3} - 9 a x^{2} - 24 a x - 16 a + 9 x - b x^{2} - 5 b x - 4 b - c (x + 1)}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.13

Simplify the numerator.

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Step 2.13.1

Apply the distributive property.

$\frac{- a x^{3} - 9 a x^{2} - 24 a x - 16 a + 9 x - b x^{2} - 5 b x - 4 b - c x - c \cdot 1}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.13.2

Multiply $- 1$ by $1$ .

$\frac{- a x^{3} - 9 a x^{2} - 24 a x - 16 a + 9 x - b x^{2} - 5 b x - 4 b - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.14

Factor $- 1$ out of $- a x^{3}$ .

$\frac{- (a x^{3}) - 9 a x^{2} - 24 a x - 16 a + 9 x - b x^{2} - 5 b x - 4 b - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.15

Factor $- 1$ out of $- 9 a x^{2}$ .

$\frac{- (a x^{3}) - (9 a x^{2}) - 24 a x - 16 a + 9 x - b x^{2} - 5 b x - 4 b - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.16

Factor $- 1$ out of $- (a x^{3}) - (9 a x^{2})$ .

$\frac{- (a x^{3} + 9 a x^{2}) - 24 a x - 16 a + 9 x - b x^{2} - 5 b x - 4 b - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.17

Factor $- 1$ out of $- 24 a x$ .

$\frac{- (a x^{3} + 9 a x^{2}) - (24 a x) - 16 a + 9 x - b x^{2} - 5 b x - 4 b - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.18

Factor $- 1$ out of $- (a x^{3} + 9 a x^{2}) - (24 a x)$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x) - 16 a + 9 x - b x^{2} - 5 b x - 4 b - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.19

Factor $- 1$ out of $- 16 a$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x) - (16 a) + 9 x - b x^{2} - 5 b x - 4 b - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.20

Factor $- 1$ out of $- (a x^{3} + 9 a x^{2} + 24 a x) - (16 a)$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x + 16 a) + 9 x - b x^{2} - 5 b x - 4 b - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.21

Factor $- 1$ out of $9 x$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x + 16 a) - (- 9 x) - b x^{2} - 5 b x - 4 b - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.22

Factor $- 1$ out of $- (a x^{3} + 9 a x^{2} + 24 a x + 16 a) - (- 9 x)$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x) - b x^{2} - 5 b x - 4 b - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.23

Factor $- 1$ out of $- b x^{2}$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x) - (b x^{2}) - 5 b x - 4 b - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.24

Factor $- 1$ out of $- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x) - (b x^{2})$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2}) - 5 b x - 4 b - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.25

Factor $- 1$ out of $- 5 b x$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2}) - (5 b x) - 4 b - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.26

Factor $- 1$ out of $- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2}) - (5 b x)$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2} + 5 b x) - 4 b - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.27

Factor $- 1$ out of $- 4 b$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2} + 5 b x) - (4 b) - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.28

Factor $- 1$ out of $- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2} + 5 b x) - (4 b)$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2} + 5 b x + 4 b) - c x - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.29

Factor $- 1$ out of $- c x$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2} + 5 b x + 4 b) - (c x) - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.30

Factor $- 1$ out of $- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2} + 5 b x + 4 b) - (c x)$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2} + 5 b x + 4 b + c x) - c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.31

Factor $- 1$ out of $- c$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2} + 5 b x + 4 b + c x) - (c)}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.32

Factor $- 1$ out of $- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2} + 5 b x + 4 b + c x) - (c)$ .

$\frac{- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2} + 5 b x + 4 b + c x + c)}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.33

Rewrite $- (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2} + 5 b x + 4 b + c x + c)$ as $- 1 (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2} + 5 b x + 4 b + c x + c)$ .

$\frac{- 1 (a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2} + 5 b x + 4 b + c x + c)}{{(x + 4)}^{2} (x + 1)} = 0$

Step 2.34

Move the negative in front of the fraction.

$- \frac{a x^{3} + 9 a x^{2} + 24 a x + 16 a - 9 x + b x^{2} + 5 b x + 4 b + c x + c}{{(x + 4)}^{2} (x + 1)} = 0$

Step 3

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.